3.714 \(\int \frac{x^2 (c+d x)^{5/2}}{\sqrt{a+b x}} \, dx\)

Optimal. Leaf size=314 \[ \frac{\sqrt{a+b x} (c+d x)^{5/2} \left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right )}{240 b^3 d^2}+\frac{\sqrt{a+b x} (c+d x)^{3/2} (b c-a d) \left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right )}{192 b^4 d^2}+\frac{\sqrt{a+b x} \sqrt{c+d x} (b c-a d)^2 \left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right )}{128 b^5 d^2}+\frac{(b c-a d)^3 \left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{128 b^{11/2} d^{5/2}}-\frac{3 \sqrt{a+b x} (c+d x)^{7/2} (3 a d+b c)}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d} \]

[Out]

((b*c - a*d)^2*(3*b^2*c^2 + 14*a*b*c*d + 63*a^2*d^2)*Sqrt[a + b*x]*Sqrt[c + d*x])/(128*b^5*d^2) + ((b*c - a*d)
*(3*b^2*c^2 + 14*a*b*c*d + 63*a^2*d^2)*Sqrt[a + b*x]*(c + d*x)^(3/2))/(192*b^4*d^2) + ((3*b^2*c^2 + 14*a*b*c*d
 + 63*a^2*d^2)*Sqrt[a + b*x]*(c + d*x)^(5/2))/(240*b^3*d^2) - (3*(b*c + 3*a*d)*Sqrt[a + b*x]*(c + d*x)^(7/2))/
(40*b^2*d^2) + (x*Sqrt[a + b*x]*(c + d*x)^(7/2))/(5*b*d) + ((b*c - a*d)^3*(3*b^2*c^2 + 14*a*b*c*d + 63*a^2*d^2
)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(128*b^(11/2)*d^(5/2))

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Rubi [A]  time = 0.28086, antiderivative size = 314, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273, Rules used = {90, 80, 50, 63, 217, 206} \[ \frac{\sqrt{a+b x} (c+d x)^{5/2} \left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right )}{240 b^3 d^2}+\frac{\sqrt{a+b x} (c+d x)^{3/2} (b c-a d) \left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right )}{192 b^4 d^2}+\frac{\sqrt{a+b x} \sqrt{c+d x} (b c-a d)^2 \left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right )}{128 b^5 d^2}+\frac{(b c-a d)^3 \left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{128 b^{11/2} d^{5/2}}-\frac{3 \sqrt{a+b x} (c+d x)^{7/2} (3 a d+b c)}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d} \]

Antiderivative was successfully verified.

[In]

Int[(x^2*(c + d*x)^(5/2))/Sqrt[a + b*x],x]

[Out]

((b*c - a*d)^2*(3*b^2*c^2 + 14*a*b*c*d + 63*a^2*d^2)*Sqrt[a + b*x]*Sqrt[c + d*x])/(128*b^5*d^2) + ((b*c - a*d)
*(3*b^2*c^2 + 14*a*b*c*d + 63*a^2*d^2)*Sqrt[a + b*x]*(c + d*x)^(3/2))/(192*b^4*d^2) + ((3*b^2*c^2 + 14*a*b*c*d
 + 63*a^2*d^2)*Sqrt[a + b*x]*(c + d*x)^(5/2))/(240*b^3*d^2) - (3*(b*c + 3*a*d)*Sqrt[a + b*x]*(c + d*x)^(7/2))/
(40*b^2*d^2) + (x*Sqrt[a + b*x]*(c + d*x)^(7/2))/(5*b*d) + ((b*c - a*d)^3*(3*b^2*c^2 + 14*a*b*c*d + 63*a^2*d^2
)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(128*b^(11/2)*d^(5/2))

Rule 90

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a + b*
x)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 3)), x] + Dist[1/(d*f*(n + p + 3)), Int[(c + d*x)^n*(e +
 f*x)^p*Simp[a^2*d*f*(n + p + 3) - b*(b*c*e + a*(d*e*(n + 1) + c*f*(p + 1))) + b*(a*d*f*(n + p + 4) - b*(d*e*(
n + 2) + c*f*(p + 2)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 3, 0]

Rule 80

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(c + d*x)
^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 2)), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
 /; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{x^2 (c+d x)^{5/2}}{\sqrt{a+b x}} \, dx &=\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d}+\frac{\int \frac{(c+d x)^{5/2} \left (-a c-\frac{3}{2} (b c+3 a d) x\right )}{\sqrt{a+b x}} \, dx}{5 b d}\\ &=-\frac{3 (b c+3 a d) \sqrt{a+b x} (c+d x)^{7/2}}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d}+\frac{\left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \int \frac{(c+d x)^{5/2}}{\sqrt{a+b x}} \, dx}{80 b^2 d^2}\\ &=\frac{\left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{5/2}}{240 b^3 d^2}-\frac{3 (b c+3 a d) \sqrt{a+b x} (c+d x)^{7/2}}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d}+\frac{\left ((b c-a d) \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right )\right ) \int \frac{(c+d x)^{3/2}}{\sqrt{a+b x}} \, dx}{96 b^3 d^2}\\ &=\frac{(b c-a d) \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{192 b^4 d^2}+\frac{\left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{5/2}}{240 b^3 d^2}-\frac{3 (b c+3 a d) \sqrt{a+b x} (c+d x)^{7/2}}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d}+\frac{\left ((b c-a d)^2 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right )\right ) \int \frac{\sqrt{c+d x}}{\sqrt{a+b x}} \, dx}{128 b^4 d^2}\\ &=\frac{(b c-a d)^2 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} \sqrt{c+d x}}{128 b^5 d^2}+\frac{(b c-a d) \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{192 b^4 d^2}+\frac{\left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{5/2}}{240 b^3 d^2}-\frac{3 (b c+3 a d) \sqrt{a+b x} (c+d x)^{7/2}}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d}+\frac{\left ((b c-a d)^3 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right )\right ) \int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx}{256 b^5 d^2}\\ &=\frac{(b c-a d)^2 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} \sqrt{c+d x}}{128 b^5 d^2}+\frac{(b c-a d) \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{192 b^4 d^2}+\frac{\left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{5/2}}{240 b^3 d^2}-\frac{3 (b c+3 a d) \sqrt{a+b x} (c+d x)^{7/2}}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d}+\frac{\left ((b c-a d)^3 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x}\right )}{128 b^6 d^2}\\ &=\frac{(b c-a d)^2 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} \sqrt{c+d x}}{128 b^5 d^2}+\frac{(b c-a d) \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{192 b^4 d^2}+\frac{\left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{5/2}}{240 b^3 d^2}-\frac{3 (b c+3 a d) \sqrt{a+b x} (c+d x)^{7/2}}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d}+\frac{\left ((b c-a d)^3 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{128 b^6 d^2}\\ &=\frac{(b c-a d)^2 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} \sqrt{c+d x}}{128 b^5 d^2}+\frac{(b c-a d) \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{3/2}}{192 b^4 d^2}+\frac{\left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \sqrt{a+b x} (c+d x)^{5/2}}{240 b^3 d^2}-\frac{3 (b c+3 a d) \sqrt{a+b x} (c+d x)^{7/2}}{40 b^2 d^2}+\frac{x \sqrt{a+b x} (c+d x)^{7/2}}{5 b d}+\frac{(b c-a d)^3 \left (3 b^2 c^2+14 a b c d+63 a^2 d^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{128 b^{11/2} d^{5/2}}\\ \end{align*}

Mathematica [A]  time = 1.21091, size = 239, normalized size = 0.76 \[ \frac{\sqrt{a+b x} (c+d x)^{7/2} \left (\frac{\left (63 a^2 d^2+14 a b c d+3 b^2 c^2\right ) \left (\sqrt{d} \sqrt{a+b x} \sqrt{\frac{b (c+d x)}{b c-a d}} \left (15 a^2 d^2-10 a b d (4 c+d x)+b^2 \left (33 c^2+26 c d x+8 d^2 x^2\right )\right )+15 (b c-a d)^{5/2} \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b c-a d}}\right )\right )}{48 b^4 d^{3/2} \sqrt{a+b x} (c+d x)^3 \sqrt{\frac{b (c+d x)}{b c-a d}}}-\frac{9 a}{b}-\frac{3 c}{d}+8 x\right )}{40 b d} \]

Antiderivative was successfully verified.

[In]

Integrate[(x^2*(c + d*x)^(5/2))/Sqrt[a + b*x],x]

[Out]

(Sqrt[a + b*x]*(c + d*x)^(7/2)*((-9*a)/b - (3*c)/d + 8*x + ((3*b^2*c^2 + 14*a*b*c*d + 63*a^2*d^2)*(Sqrt[d]*Sqr
t[a + b*x]*Sqrt[(b*(c + d*x))/(b*c - a*d)]*(15*a^2*d^2 - 10*a*b*d*(4*c + d*x) + b^2*(33*c^2 + 26*c*d*x + 8*d^2
*x^2)) + 15*(b*c - a*d)^(5/2)*ArcSinh[(Sqrt[d]*Sqrt[a + b*x])/Sqrt[b*c - a*d]]))/(48*b^4*d^(3/2)*Sqrt[a + b*x]
*(c + d*x)^3*Sqrt[(b*(c + d*x))/(b*c - a*d)])))/(40*b*d)

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Maple [B]  time = 0.022, size = 788, normalized size = 2.5 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(d*x+c)^(5/2)/(b*x+a)^(1/2),x)

[Out]

-1/3840*(d*x+c)^(1/2)*(b*x+a)^(1/2)*(-768*x^4*b^4*d^4*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+864*x^3*a*b^3*d^4*((
b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)-2016*x^3*b^4*c*d^3*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)-1008*x^2*a^2*b^2*d^4*
((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+2368*x^2*a*b^3*c*d^3*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)-1488*x^2*b^4*c^2*
d^2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+945*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*
d)^(1/2))*a^5*d^5-2625*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^4*b*c*d^4
+2250*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^3*b^2*c^2*d^3-450*ln(1/2*(
2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a^2*b^3*c^3*d^2-75*ln(1/2*(2*b*d*x+2*((b*x
+a)*(d*x+c))^(1/2)*(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*a*b^4*c^4*d-45*ln(1/2*(2*b*d*x+2*((b*x+a)*(d*x+c))^(1/2)*
(b*d)^(1/2)+a*d+b*c)/(b*d)^(1/2))*b^5*c^5+1260*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)*x*a^3*b*d^4-2996*(b*d)^(1/2
)*((b*x+a)*(d*x+c))^(1/2)*x*a^2*b^2*c*d^3+1924*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)*x*a*b^3*c^2*d^2-60*(b*d)^(1
/2)*((b*x+a)*(d*x+c))^(1/2)*x*b^4*c^3*d-1890*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)*a^4*d^4+4620*(b*d)^(1/2)*((b*
x+a)*(d*x+c))^(1/2)*a^3*b*c*d^3-3128*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)*a^2*b^2*c^2*d^2+180*(b*d)^(1/2)*((b*x
+a)*(d*x+c))^(1/2)*a*b^3*c^3*d+90*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/2)*b^4*c^4)/b^5/d^2/((b*x+a)*(d*x+c))^(1/2)
/(b*d)^(1/2)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d*x+c)^(5/2)/(b*x+a)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 2.64971, size = 1600, normalized size = 5.1 \begin{align*} \left [-\frac{15 \,{\left (3 \, b^{5} c^{5} + 5 \, a b^{4} c^{4} d + 30 \, a^{2} b^{3} c^{3} d^{2} - 150 \, a^{3} b^{2} c^{2} d^{3} + 175 \, a^{4} b c d^{4} - 63 \, a^{5} d^{5}\right )} \sqrt{b d} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} - 4 \,{\left (2 \, b d x + b c + a d\right )} \sqrt{b d} \sqrt{b x + a} \sqrt{d x + c} + 8 \,{\left (b^{2} c d + a b d^{2}\right )} x\right ) - 4 \,{\left (384 \, b^{5} d^{5} x^{4} - 45 \, b^{5} c^{4} d - 90 \, a b^{4} c^{3} d^{2} + 1564 \, a^{2} b^{3} c^{2} d^{3} - 2310 \, a^{3} b^{2} c d^{4} + 945 \, a^{4} b d^{5} + 144 \,{\left (7 \, b^{5} c d^{4} - 3 \, a b^{4} d^{5}\right )} x^{3} + 8 \,{\left (93 \, b^{5} c^{2} d^{3} - 148 \, a b^{4} c d^{4} + 63 \, a^{2} b^{3} d^{5}\right )} x^{2} + 2 \,{\left (15 \, b^{5} c^{3} d^{2} - 481 \, a b^{4} c^{2} d^{3} + 749 \, a^{2} b^{3} c d^{4} - 315 \, a^{3} b^{2} d^{5}\right )} x\right )} \sqrt{b x + a} \sqrt{d x + c}}{7680 \, b^{6} d^{3}}, -\frac{15 \,{\left (3 \, b^{5} c^{5} + 5 \, a b^{4} c^{4} d + 30 \, a^{2} b^{3} c^{3} d^{2} - 150 \, a^{3} b^{2} c^{2} d^{3} + 175 \, a^{4} b c d^{4} - 63 \, a^{5} d^{5}\right )} \sqrt{-b d} \arctan \left (\frac{{\left (2 \, b d x + b c + a d\right )} \sqrt{-b d} \sqrt{b x + a} \sqrt{d x + c}}{2 \,{\left (b^{2} d^{2} x^{2} + a b c d +{\left (b^{2} c d + a b d^{2}\right )} x\right )}}\right ) - 2 \,{\left (384 \, b^{5} d^{5} x^{4} - 45 \, b^{5} c^{4} d - 90 \, a b^{4} c^{3} d^{2} + 1564 \, a^{2} b^{3} c^{2} d^{3} - 2310 \, a^{3} b^{2} c d^{4} + 945 \, a^{4} b d^{5} + 144 \,{\left (7 \, b^{5} c d^{4} - 3 \, a b^{4} d^{5}\right )} x^{3} + 8 \,{\left (93 \, b^{5} c^{2} d^{3} - 148 \, a b^{4} c d^{4} + 63 \, a^{2} b^{3} d^{5}\right )} x^{2} + 2 \,{\left (15 \, b^{5} c^{3} d^{2} - 481 \, a b^{4} c^{2} d^{3} + 749 \, a^{2} b^{3} c d^{4} - 315 \, a^{3} b^{2} d^{5}\right )} x\right )} \sqrt{b x + a} \sqrt{d x + c}}{3840 \, b^{6} d^{3}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d*x+c)^(5/2)/(b*x+a)^(1/2),x, algorithm="fricas")

[Out]

[-1/7680*(15*(3*b^5*c^5 + 5*a*b^4*c^4*d + 30*a^2*b^3*c^3*d^2 - 150*a^3*b^2*c^2*d^3 + 175*a^4*b*c*d^4 - 63*a^5*
d^5)*sqrt(b*d)*log(8*b^2*d^2*x^2 + b^2*c^2 + 6*a*b*c*d + a^2*d^2 - 4*(2*b*d*x + b*c + a*d)*sqrt(b*d)*sqrt(b*x
+ a)*sqrt(d*x + c) + 8*(b^2*c*d + a*b*d^2)*x) - 4*(384*b^5*d^5*x^4 - 45*b^5*c^4*d - 90*a*b^4*c^3*d^2 + 1564*a^
2*b^3*c^2*d^3 - 2310*a^3*b^2*c*d^4 + 945*a^4*b*d^5 + 144*(7*b^5*c*d^4 - 3*a*b^4*d^5)*x^3 + 8*(93*b^5*c^2*d^3 -
 148*a*b^4*c*d^4 + 63*a^2*b^3*d^5)*x^2 + 2*(15*b^5*c^3*d^2 - 481*a*b^4*c^2*d^3 + 749*a^2*b^3*c*d^4 - 315*a^3*b
^2*d^5)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(b^6*d^3), -1/3840*(15*(3*b^5*c^5 + 5*a*b^4*c^4*d + 30*a^2*b^3*c^3*d^2
 - 150*a^3*b^2*c^2*d^3 + 175*a^4*b*c*d^4 - 63*a^5*d^5)*sqrt(-b*d)*arctan(1/2*(2*b*d*x + b*c + a*d)*sqrt(-b*d)*
sqrt(b*x + a)*sqrt(d*x + c)/(b^2*d^2*x^2 + a*b*c*d + (b^2*c*d + a*b*d^2)*x)) - 2*(384*b^5*d^5*x^4 - 45*b^5*c^4
*d - 90*a*b^4*c^3*d^2 + 1564*a^2*b^3*c^2*d^3 - 2310*a^3*b^2*c*d^4 + 945*a^4*b*d^5 + 144*(7*b^5*c*d^4 - 3*a*b^4
*d^5)*x^3 + 8*(93*b^5*c^2*d^3 - 148*a*b^4*c*d^4 + 63*a^2*b^3*d^5)*x^2 + 2*(15*b^5*c^3*d^2 - 481*a*b^4*c^2*d^3
+ 749*a^2*b^3*c*d^4 - 315*a^3*b^2*d^5)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(b^6*d^3)]

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(d*x+c)**(5/2)/(b*x+a)**(1/2),x)

[Out]

Timed out

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Giac [B]  time = 1.9273, size = 1195, normalized size = 3.81 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d*x+c)^(5/2)/(b*x+a)^(1/2),x, algorithm="giac")

[Out]

1/1920*(80*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*sqrt(b*x + a)*(2*(b*x + a)*(4*(b*x + a)/b^2 + (b^6*c*d^3 - 13*
a*b^5*d^4)/(b^7*d^4)) - 3*(b^7*c^2*d^2 + 2*a*b^6*c*d^3 - 11*a^2*b^5*d^4)/(b^7*d^4)) - 3*(b^3*c^3 + a*b^2*c^2*d
 + 3*a^2*b*c*d^2 - 5*a^3*d^3)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b
*d)*b*d^2))*c^2*abs(b)/b^2 + 20*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(b*x + a)*(4*(b*x + a)*(6*(b*x + a)/b^
3 + (b^12*c*d^5 - 25*a*b^11*d^6)/(b^14*d^6)) - (5*b^13*c^2*d^4 + 14*a*b^12*c*d^5 - 163*a^2*b^11*d^6)/(b^14*d^6
)) + 3*(5*b^14*c^3*d^3 + 9*a*b^13*c^2*d^4 + 15*a^2*b^12*c*d^5 - 93*a^3*b^11*d^6)/(b^14*d^6))*sqrt(b*x + a) + 3
*(5*b^4*c^4 + 4*a*b^3*c^3*d + 6*a^2*b^2*c^2*d^2 + 20*a^3*b*c*d^3 - 35*a^4*d^4)*log(abs(-sqrt(b*d)*sqrt(b*x + a
) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^2*d^3))*c*d*abs(b)/b^2 + (sqrt(b^2*c + (b*x + a)*b*d -
a*b*d)*(2*(4*(b*x + a)*(6*(b*x + a)*(8*(b*x + a)/b^4 + (b^20*c*d^7 - 41*a*b^19*d^8)/(b^23*d^8)) - (7*b^21*c^2*
d^6 + 26*a*b^20*c*d^7 - 513*a^2*b^19*d^8)/(b^23*d^8)) + 5*(7*b^22*c^3*d^5 + 19*a*b^21*c^2*d^6 + 37*a^2*b^20*c*
d^7 - 447*a^3*b^19*d^8)/(b^23*d^8))*(b*x + a) - 15*(7*b^23*c^4*d^4 + 12*a*b^22*c^3*d^5 + 18*a^2*b^21*c^2*d^6 +
 28*a^3*b^20*c*d^7 - 193*a^4*b^19*d^8)/(b^23*d^8))*sqrt(b*x + a) - 15*(7*b^5*c^5 + 5*a*b^4*c^4*d + 6*a^2*b^3*c
^3*d^2 + 10*a^3*b^2*c^2*d^3 + 35*a^4*b*c*d^4 - 63*a^5*d^5)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*
x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^3*d^4))*d^2*abs(b)/b^2)/b